(x+2)(x^2-2x+4)=0

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Solution for (x+2)(x^2-2x+4)=0 equation: 


Simplifying
(x + 2)(x2 + -2x + 4) = 0

Reorder the terms:
(2 + x)(x2 + -2x + 4) = 0

Reorder the terms:
(2 + x)(4 + -2x + x2) = 0

Multiply (2 + x) * (4 + -2x + x2)
(2(4 + -2x + x2) + x(4 + -2x + x2)) = 0
((4 * 2 + -2x * 2 + x2 * 2) + x(4 + -2x + x2)) = 0
((8 + -4x + 2x2) + x(4 + -2x + x2)) = 0
(8 + -4x + 2x2 + (4 * x + -2x * x + x2 * x)) = 0
(8 + -4x + 2x2 + (4x + -2x2 + x3)) = 0

Reorder the terms:
(8 + -4x + 4x + 2x2 + -2x2 + x3) = 0

Combine like terms: -4x + 4x = 0
(8 + 0 + 2x2 + -2x2 + x3) = 0
(8 + 2x2 + -2x2 + x3) = 0

Combine like terms: 2x2 + -2x2 = 0
(8 + 0 + x3) = 0
(8 + x3) = 0

Solving
8 + x3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + x3 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + x3 = 0 + -8
x3 = 0 + -8

Combine like terms: 0 + -8 = -8
x3 = -8

Simplifying
x3 = -8

Reorder the terms:
8 + x3 = -8 + 8

Combine like terms: -8 + 8 = 0
8 + x3 = 0

The solution to this equation could not be determined.

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